Let's dive deep into the regular expression a(a|b)*b
and understand exactly how it works, component by component.
First, let's restate the rule we want to enforce:
1. The string must begin with the character a
.
2. The string must end with the character b
.
3. Any characters in between the first a
and the last b
can be either a
or b
.
The regular expression a(a|b)*b
is a concise way to write these rules. We can think of it as having three distinct parts that correspond perfectly to our requirements.
Think of the expression as: [The Beginning] [The Middle] [The End]
| Part | Regex Component | What it Means |
| :------------ | :-------------- | :--------------------------------------------- |
| Beginning | a
| The string must start with a literal 'a'. |
| Middle | (a|b)*
| Between the start and end, there can be anything. |
| End | b
| The string must end with a literal 'b'. |
Now, let's analyze each component in detail.
a
)a(a|b)*b
^
This is the simplest part. In regular expressions, when a character doesn't have a special meaning (like *
, +
, |
, (
, )
), it is a literal.
a
: This is a literal match. It asserts that the pattern must start with the character 'a'. The regular expression engine will first look at the very beginning of a string. If it's not an 'a', the string is immediately rejected without checking the rest.(a|b)*
)This is the most complex and flexible part of the expression. Let's break it down from the inside out.
a(a|b)*b
^^^^^
a|b
(The Alternation)|
is the OR operator in regular expressions. It's used to specify alternatives.a|b
means "match a single character that is either an 'a' or a 'b'".(...)
(The Parentheses)(a|b)
treats the "a or b" choice as one whole piece. This is crucial because we want to apply the next operator (the *
) to the entire choice, not just to the b
.a|b*
would mean "match an 'a' OR match a 'b' zero or more times", which is a completely different rule.*
is a quantifier. It applies to the element immediately preceding it, which is our group (a|b)
.*
means "match the preceding element zero or more times".ab
, is accepted. The middle part simply doesn't exist.a
or a single b
(e.g., in aab
or abb
).a
s and b
s of any length (e.g., aaabbab
in the string aaabbabb
).Putting the middle part together: (a|b)*
means "match a sequence containing any number of 'a's and 'b's, including no characters at all".
b
)`
a(a|b)*b
^
`
b
: Just like the a
at the beginning, this is a literal match. It asserts that the character at the very end of the string must be a 'b'. If a string starts with 'a' and has a valid middle but ends in 'a', it will be rejected.A great way to visualize this is to think of it as building a sandwich.
a
: This is the top slice of bread. Every valid sandwich must have it.
b
: This is the bottom slice of bread. Every valid sandwich must have it.
`(a|b)`: These are the fillings.
* The `(a|b)` part says you are only allowed to use 'a' and 'b' as ingredients. No 'c', no 'd'.
* The `*` part says you can have as many layers of filling as you want (`ababab...`), or you can have **no filling at all** (just the two slices of bread, `ab`).
When a regex engine sees the string aaabb
against the pattern a(a|b)*b
:
a
? Yes, aaabb
does. Proceed.b
? Yes, aaabb
does. Proceed.a
and the last b
. The substring is aab
.(a|b)*
match aab
?(a|b)
match the first a
? Yes.(a|b)
match the second a
? Yes.(a|b)
match the b
? Yes.aaabb
is a match.When it sees the string aba
:
a
? Yes.b
? No, it ends with a
.